上個(gè)禮拜進修了下(xià)金字塔的繪制，然後這周有看了看正方體的繪制，經由過程依次繪制6個(gè)面來繪制正方體，整體代碼跟前次的金三角沒有差别，隻是坐(zuò)标點，色彩，已經繪制的代碼有點差别，上代碼看看
//這是坐(zuò)标
private static float[][] cubeVertexCoords = new float[][] {
new float[] { // top
1, 1,-1,
-1, 1,-1,
-1, 1, 1,
1, 1, 1
},
new float[] { // bottom
1,-1, 1,
-1,-1, 1,
-1,-1,-1,
1,-1,-1
},
new float[] { // front
1, 1, 1,
-1, 1, 1,
-1,-1, 1,
1,-1, 1
},
new float[] { // back
1,-1,-1,
-1,-1,-1,
-1, 1,-1,
1, 1,-1
},
new float[] { // left
-1, 1, 1,
-1, 1,-1,
-1,-1,-1,
-1,-1, 1
},
new float[] { // right
1, 1,-1,
1, 1, 1,
1,-1, 1,
1,-1,-1
},
};
//這是色彩
private static float[] cubeColors = new float[] {
0,1,0,1,
1,0.5f,0,1,
1,0,0,1,
1,1,0,1,
0,0,1,1,
1,0,1,1
};
然後必須要把呀轉化為FloatBuffer  ，如(rú)許就可(kě)以應用了
private static FloatBuffer[] cubeVertexBfr;

private static FloatBuffer  cubeColorBfr;
轉化我寫了個(gè)轉化的對象類
public  class BufferUtil {
private static FloatBuffer floatBuffer;

public static FloatBuffer  floatToBuffer(float[] f){

ByteBuffer  buffer  =ByteBuffer.allocateDirect(f.length*4);

buffer.order(ByteOrder.nativeOrder());
floatBuffer  =buffer.asFloatBuffer();
floatBuffer.put(f);
floatBuffer.position(0);
return floatBuffer;
}


下(xià)邊是繪制的代碼
gl.glEnableClientState(GL10.GL_VERTEX_ARRAY);//在上邊打開鄙人邊就要封閉，這個(gè)原因是然河畔的繪制不會複竽暌姑前邊的色彩等的樣式

gl.glEnableClientState(GL10.GL_COLOR_ARRAY);
for (int i = 0; i < 6; i++) // draw each face
{
gl.glVertexPointer(3, GL10.GL_FLOAT, 0, cubeVertexBfr[i]);

gl.glColorPointer(4, GL10.GL_FLOAT, 0, cubeColorBfr);
gl.glDrawArrays(GL10.GL_TRIANGLE_FAN, 0, 4);
}
gl.glDisableClientState(GL10.GL_VERTEX_ARRAY);

gl.glDisableClientState(GL10.GL_COLOR_ARRAY);

}